Find a Pythagorean triplet whose one member is 16.
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★Pythagorean Triplets:
Three natural numbers m,n and p are said to form a Pythagorean Triplet (m,n,p),
if m²+n² = p².
For every natural number m>1,
we have (2m,m²-1,m²+1) as a Pythagorean Triplet.
Here,
m = 16,
2m= 2×16 = 32
m²-1 = 16² - 1 = 256 -1 = 255
m²+1 = 16²+1 = 256 +1 = 257
Therefore,
Required Pythagorean Triplet:
(32,255,257)
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