find a Pythagorean triplet whose one member is 323
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Answered by
1
Answer:
use formula 2n,n square+1,n square-1
2n=323/2=161.5
n square+1=161.5 square +1
Answered by
0
Answer:
Pythagorean triplet = 2m+m²+1+m²-1
2m=323
m =323 / 2=161.5
m²+1 =161.5 ×161.5+1=2608325
m²-1=161.5×161.5-1=26081.25
Pythagorean triplet= 323,26083025, 26081.25
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