Question

Find a pythagorean triplet whose one member is 323

Answer 1

Answer:

HEY SWEETHEART HERE IS YOUR ANSWER

When n is a member of a pythagorean tripplet then the triplet is :

n² - 1

2n

n² + 1

In our case n = 323

Doing the substitution we have :

n² - 1 = 323² - 1 = 104328

2n = 323 × 2 = 646

n² + 1 = 104330

The tripplet is thus :

104328, 646, 104330

Answer 2

Answer:

(36,323,325)

Step-by-step explanation:

It is easy to construct sets of Pythagorean Triples.

When m​​​​​​ and n are any two positive integers (m < n):

a = n2 - m2

b = 2nm

c = n2 + m2

Then a, b, and c form a Pythagorean Triple.

So let a= 323

But we know

323= 324-1

=18²-1²

So n=18

m=1

b=2nm

=2*18*1

=36

c=n²+m²

=18²+1²

= 324+1

=325

So the triplet =(36,323,325)

Hope you have understood.