find a Pythagorean triplet whose one member is 323
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Step-by-step explanation:
When n is a member of a pythagorean tripplet then the triplet is :
n² - 1
2n
n² + 1
In our case n = 323
Doing the substitution we have :
n² - 1 = 323² - 1 = 104328
2n = 323 × 2 = 646
n² + 1 = 104330
The tripplet is thus :
104328, 646, 104330
hope it helps !.
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