Find a Pythagorean triplet whose one member is 323. Please give me correct answer
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Pythagorean triples is in the form of n^2 + 1, n^2-1,2n..... but is has some exception...(n is an integer)
323 is odd no. so it can not be in the form of 2n...
So, 323= n^2-1
So, we get n as 18 which is an integer...
Therefore, 2n = 36
n^2+1 = 325
Hence the triple is (36,323,325)
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