Question

Find a Pythagorean triplet with 26 as the largest member.

Answer 1

Answer:

here is your answer

Solution

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to find pythagoran triplet

( 2m, m^2 - 1 , m^2 +1 )

in this form we have to find

m^2 +1 = 26

m^2 = 25

m= 5

so m^2-1 = 25-1 = 24

and, 2m = 5x2 = 10

thus the triplet so formed is 26,24,10

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