Question

Find a Pythagorean triplet with 37 as a member

Answer 1

Answer:

As we know 2m, m 2 + 1 and m2 - 1 form a Pythagorean triplet for any number, m > 1.

Let's assume

M^2+1=37

Then, M^2=36

And M=6

Now put the value of M

2M = 12

M^2+1=37

M^2-1=35

The triplets are 37, 35 and 12