Question

find a Pythagorean triplets whose one number is 12​

Answer 1

Answer:

2m, m^2-1, m^2+1

let 2m = 12

2m=12

m=12/2

m=6

m^2-1=6^2-1

= 36-1

=35

m^2+1=6^2+1

=36+1

37

triplets (12, 35, 37)

Answer 2

Answer:

12,35,37 are the required triplets.

Step-by-step explanation:

(2m,m^2-1,m^2+1)

2m=12

m=6

First member =12

Second member= m^2-1

=6^2-1

=36-1

=35

Third member= m^2+1

=6^2+1

=36+1

=37

Therefore, the Pythagorean triplets are 12,35,37.

Hope this will help you.