Find a pythagrean triplet whose one member is 14
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smallest member = 2m
middle number = m square - 1
largest number = m square
let 2m = 14
then m = 7
m^2 - 1 = 7*7 -1
= 49- 1
=48
m^2 + 1 = 7*7 + 1
= 49 + 1
= 50
middle number = m square - 1
largest number = m square
let 2m = 14
then m = 7
m^2 - 1 = 7*7 -1
= 49- 1
=48
m^2 + 1 = 7*7 + 1
= 49 + 1
= 50
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