Question

find a pythogorean triplet whose one member is a) 10 b) 14 c) 16 d) 18​

Answer 1

Step-by-step explanation:

Pythagorean triplets:

For any natural number m > 1, we have (2m) ² + (m2 – 1)²= (m2 + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.

 =========================================================

Solution:

i)

Let  2m = 6

 m = 3

m²+ 1 = 3² + 1= 9 + 1 = 10

m²- 1 = 3 2 - 1 = 9 - 1 = 8

check:

6 ² + 8² = 36 + 64 = 100 = 10²

Hence, the triplet is 6, 8 & 10 

ii)

Let  2 m = 14

 m = 7

 m² + 1 = 7²+ 1 = 49 + 1 = 50

m²- 1 = 7² - 1 = 49 - 1 = 48

check:

14² + 48² = 196 + 1304 = 2500 = 50²

Hence, the triplet is 14, 48, and 50 

iii)

Let 2 m = 16,

 m = 8

 m² + 1 = 8² + 1 = 64 + 1 = 65

m²- 1 = 8 2 - 1 = 64 - 1 = 63

check:

16² + 63² = 256 + 3969 = 4225 = 65²

Hence, the triplet is 16, 63 & 65 

 

iv)

Let  2 m = 18

 

m = 9

m² + 1 = 9² + 1 = 81 + 1 = 82

 m² - 1 = 9² - 1 = 81 - 1 = 80

check:

18²+ 80² = 324 + 6400 = 6724 = 82²

Hence, the triplet is 18, 80 & 82 

==========================================================

Hope this will help you........

Answer 2

Answer:

18, 80, 82

hope it's help u

mark as a brainlist