Math, asked by sreelakshmi58, 6 months ago

find a pythogorean triplets in which one member is 26,explain​

Answers

Answered by Anonymous
1

Answer:

Triplets are in the form 2m, m^2-1, m^2+1

2m=26, So, m=26/2 =13

m^2-1= 13^2-1=169-1=168

m^2+1=13^2+1=169+1=170

Triplets are: 26, 168, 170

This is your answer.

Hope this helps you!

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