find a pythogorean triplets in which one member is 26,explain
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Triplets are in the form 2m, m^2-1, m^2+1
2m=26, So, m=26/2 =13
m^2-1= 13^2-1=169-1=168
m^2+1=13^2+1=169+1=170
Triplets are: 26, 168, 170
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