Question

find a Q.P whose sum of zeroes are product of zeroes given 1/√3+1,1/√3-1 respectively​

Answer 1

Answer:

Required quadratic polynomial is

x^{2} -\sqrt{3} x + \frac{1}{\sqrt{3} }x2−3x+31

Step-by-step explanation:

We know that,

Quadratic polynomial = x^{2}x2 - (sum of zeroes)x + product of zeroes

                                     = x^{2} -\sqrt{3} x + \frac{1}{\sqrt{3} }=x2−3x+31

                                   

Answer 2

Answer:

0 = 2x^2-(√3+1)x+ √3+1

Step-by-step explanation:

p(x) = k(x^2-(sum of zeroes)x + product of zeroes)

0 = k(x^2-(1/√3+1)x+ 1/√3-1)

0 = x^2-(1/√3+1)x+ 1/√3-1

Rationalising 1/√3+1

√3-1/3-1 = √3-1/2

Similarly Rationalising 1/√3-1

√3+1/2

Substituting in equation

0 = x^2-(√3+1/2)x+ √3+1/2

0 = 2x^2-(√3+1)x+ √3+1

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