Find a qiadratic polynomial whose zeroes are = 2+√3, 2-√3
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Answer:x^2 - 4x =1 = 0
Step-by-step explanation: Zeroes = 2+root3, 2-root3
Sum of zeroes => (2+root3)+(2-root3) = 2+2 = 4 = -b/a (Coefficient of x/Coefficient of x^2)
Product of zeroes => (2+root3)*(2-root3) = 2^2 - root3^2 = 4-3 =1 = c/a (constan term/ coefficient of x^2)
1x^2 - 4x +1
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