find a qp whose zeroes are 2+ root 3 and 2 - root 3
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given Zeroes are , 2+√3 and 2-√3
we know that formula = x^2+(a-b)x-ab
so.sum of zeroes= 2+√3+2-√3=4
product of zeroes= 2+√3×2-√3=4-3=1
x^2-4x-1
hope it help you
we know that formula = x^2+(a-b)x-ab
so.sum of zeroes= 2+√3+2-√3=4
product of zeroes= 2+√3×2-√3=4-3=1
x^2-4x-1
hope it help you
DeeptiMohanty:
it's not -ab its +ab
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