find a quadratic equation by completing square method 2x2+x-4=0
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Answered by
1
Hey mate,
Here is your answer↓
2x^2 +x-4=0
a=2,b=1,c=-4.
Discrimant (D)=b^2-4ac.
D=(1)^2-4(2)(-4)
D=1+32
D=33.
Roots are real and unequal.
x= -b+-√D/2a
x=-(1)+-√33/2(2)
X=-1-√33/4, X=-1+√33/4.
Hope it helps u...
Here is your answer↓
2x^2 +x-4=0
a=2,b=1,c=-4.
Discrimant (D)=b^2-4ac.
D=(1)^2-4(2)(-4)
D=1+32
D=33.
Roots are real and unequal.
x= -b+-√D/2a
x=-(1)+-√33/2(2)
X=-1-√33/4, X=-1+√33/4.
Hope it helps u...
Answered by
0
2x^2 +x-4=0
a=2,b=1,c=-4.
Discrimant (D)=b^2-4ac.
D=(1)^2-4(2)(-4)
D=1+32
D=33.
Roots are real and unequal.
x= -b+-√D/2a
x=-(1)+-√33/2(2)
X=-1-√33/4, X=-1+√33/4.
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