Question

find a quadratic equation for the roots 5&-4​

Answer 1

Answer:

x² - x - 20

Step-by-step explanation:

x₁ = 5, x₂ = -4

ax² + bx +c = (x - x₁)(x -x₂)

• (x - x₁)(x -x₂) =
• (x -5) (x -(-4)) =
• (x -5)(x +4) =
• x² + 4x - 5x - 20=
• x² - x - 20

Answer 2

Answer:

(x-5)(x+4)=x^2- x-20

Step-by-step explanation:

how I can write this (x-5)(x+4)

see we can see we have given roots 5and -4

so we need to think that I can I got it .... simply we assured this (x-5)=0 , (x+4)=0

after that x=5,x=-4 .....

hopely you Understand and relat that question