Question

Find a quadratic equation whose roots are 9 and 1​

Answer 1

Answer:

X^2+10X+9

Step-by-step explanation:

Sum of roots=9+1=10

Product of roots=9 x 1=9

Equation=X^2+(sum of roots)X+(product of roots)

             =X^2+10X+9

Answer 2

Given:

roots ➡9,1

$\purple{\huge{\bold{\mathcal{Answer}}}}$

let the zeroes be X

now we have

The first zeroes

$\large{x=9}$

$\large{x-9=0......(1)}$

The second zeroes

$\large{x=1}$

$\large{x-1=0......(2)}$

Multiplying (1) and (2) we get

$\large{(x-1)(x-2)=0}$

$x {}^{2} - 2x - x + 2 = 0 \\ x {}^{2} - 3x + 2 = 0$