Question

find a quadratic equation whose sum of the roots is 5 and difference of roots is 1​

Answer 1

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Answer 2

Step-by-step explanation:

given that,

$\alpha + \beta = 5 \\ \alpha - \beta = 1$

solving eq. 1 and 2

$\alpha + \beta = 5 \\ \alpha - \beta = 1 \\ = \2alpha = 6$

2alpha = 6

alpha = 3

putting value of @ in eq. 1

alpha + beta = 5

3 + beta = 5

beta = 5 -3 = 2

so, @B = 3 × 2 = 6

by the quadratic equation formula,

x² - (@ +B)x + (@B)

x² - 5x + 6