Math, asked by meghnameghu303, 1 year ago

Find a quadratic equation whose zeroes are 3+√2 and 3-√2

Answers

Answered by Akshitha0912
3
let , f = 3+root2 and g = 3-root2
a quadratic equation whose roots are f and g is
x^2 + (f+g) + fg
= x^2 + (3+root2 + 3-root2) x+ (3+root2) (3-root2)
=x^2 + 6x+ (3^2 - root2^2)
= x^2 + 6x + 9-2
=x^2 + 6x + 7
Answered by Anonymous
1
let , f = 3+root2 and g = 3-root2
a quadratic equation whose roots are f and g is
x^2 + (f+g) + fg
= x^2 + (3+root2 + 3-root2) x+ (3+root2) (3-root2)
=x^2 + 6x+ (3^2 - root2^2)
= x^2 + 6x + 9-2
=x^2 + 6x + 7
Hope for the best

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