Math, asked by tanusharvesh2006, 1 month ago

find a quadratic polynomial each with given numbers as the sum and product of its zeroes respectively​

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Answers

Answered by tanushree830
1

Answer:

3x^2-3√2x+1

Step-by-step explanation:

Alpha +beta=-b/a

alpha×beta = C/a

Answered by amazingkurl
1

ii ) sum zeroes = √2

 \frac{ - b}{a}  =  \frac{ \sqrt{2} }{1}

\frac{  b}{a}  =  \frac{  - \sqrt{2}  \times 3}{1 \times 3}

\frac{ b}{a}  =  \frac{-3 \sqrt{2} }{3}

product of zeroes =1/3

 \frac{c}{a}  =  \frac{1}{3}

Therefore a =3 , b =- 3√2 , c = 1

Quadratic polynomial is ax²+bx+c

= 3x²- 3√2x +1

v )

sum of zeroes = - 1/4

 \frac{ - b}{a}  =  \frac{ - 1}{4}

 \frac{ b}{a}  =  \frac{ 1}{4}

product of zeroes = 1/4

 \frac{ c}{a}  =  \frac{ 1}{4}

Therefore a =4 , b = 1 , c = 1

Quadratic polynomial is ax²+bx+c

= 4x²+1x +1

or 4x²+ x +1

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