Find a quadratic polynomial each with the given number as the sum and product of its zeros respectively and find its zeros: -
1)-8/3,4/3
2)21/8,5/16
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2
Explanation:
you cam See the aboie pic for the answer
HOpe it helps
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Answered by
1
Explanation:
(1) alfa+ beta = -8/3, alfa×beta = 4/3
polynomial = x²-(-8/3)x+4/3
= x²+8/3x+4/3
= x²+(6/3+2/3)x +4/3
= x²+2x+2/3x+4/3
= x(x+2) +2/3( x+2)
= (x+2)(x+2/3)
zeroes are -2 and -2/3
(1) alfa + beta = 21/8, alfa×beta = 5/16
polynomial = x²-(21/8)x+ 5/16
x = 21/4±(√441/64-20/16) /2
= 21/4±(√361) /2
=21/4±19/2
=> x = 59/4 , x = -17/4
zeroes are 59/4 and -17/4
hope this helps you
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