Question

find a quadratic polynomial each with the given numbers as the sum and product of its zeros respectively v) -1/4,1/4​

Answer 1

GIVEN :

The zeroes are $\frac{-1}{4}$,$\frac{1}{4}$

TO FIND :

A quadratic equation with the given zeroes.

SOLUTION :

Given zeroes are $\frac{-1}{4}$ and $\frac{1}{4}$

For a quadratic equation with the given two zeroes then the formula is given by :

$x^2-(sum of the zeroes)x+product of the zeroes=0$

$Sum of the zeroes=\frac{-1}{4}+\frac{1}{4}$

$=0$

∴ Sum of the zeroes=0

$Product of the zeroes=\frac{-1}{4}\times \frac{1}{4}$

$=-\frac{1}{16}$

∴ $Product of the zeroes=-\frac{1}{16}$

Substitute the values in the formula to get quadratic equation we have that,

$x^2-0x+(-\frac{1}{16})=0$

$x^2-\frac{1}{16}=0$

∴ the required quadratic equation is $x^2-\frac{1}{16}=0$

Answer 2

x^2-(sumof zeroes)+(product of zeroes.)

first write that formula then do the question

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