Find a quadratic polynomial each with the given numbers as the sum and product of its
zeroes respectively.
1/4,-1
ii √2,1/3
iii0,√5
iv 1,1
v -1/4,1/4
vi 4,1
Answers
Step-by-step explanation:
By using formula...
x^2-Sx+p=0
1) x^2-1/4x+(-1)=0
x^2-1x-1=0*4
x^2-1x-1=0
2) x^2-√2x+1/3=0
x^2-√2x+1=0*3
x^2-√2x+1=0
3) x^2-0x+√5=0
x^2-√5
4) x^2-1x+1=0
5) x^2-(-1/4)x+1/4=0
x^2+1/4x+1/4=0
x^2+1x+1=0
6) x^2-4x+1=0
When a equation is form like ax^2+bx+c=0 you can remove that zero on right side .
↬ Solution :-
❍ (i) 1/4 , -1
➝ α + β = 1/4
➝ α × β = -1
⸕ In Quadratic polynomial,
We know that,
quadratic polynomial = x² - ( α + β )x + α × β
➝ x² - 1/4 x + (-1)
➝ x² - x/4 - 1
➝
➝ 4x² - x - 4
Hence, required polynomial will be 4x² - x -4.
❍ (ii) √2 , 1/3
➝ α + β = √2
➝ α × β = 1/3
⸕ In Quadratic polynomial,
We know that,
quadratic polynomial = x² - ( α + β )x + α × β
➝ x² - √2 x + 1/3
➝ x² - √2x +1/3
➝
➝ 3x² - 3√2x +1
Hence, required polynomial will be 3x² - 3√2x + 1.
❍ (iii) 0 , √5
➝ α + β = 0
➝ α × β = √5
⸕ In Quadratic polynomial,
We know that,
quadratic polynomial = x² - ( α + β )x + α × β
➝ x² - 0 x + 5
➝ x² + √5
Hence, required polynomial will be x² + √5
❍ (iv) 1 , 1
➝ α + β = 1
➝ α × β = 1
⸕ In Quadratic polynomial,
We know that,
quadratic polynomial = x² - ( α + β )x + α × β
➝ x² - 1 x + 1
➝ x² - x + 1
Hence, required polynomial will be x² - x + 1.
❍ (v) -1/4 , 1/4
➝ α + β = -1/4
➝ α × β = 1/4
⸕ In Quadratic polynomial,
We know that,
quadratic polynomial = x² - ( α + β )x + α × β
➝ x² - (-1/4)x + 1/4
➝ x² + x/4 + 1/4
➝
➝ 4x² + x + 1
Hence, required polynomial will be 4x² + x + 1.
❍ (vi) 4 , 1
➝ α + β = 4
➝ α × β = 1
⸕ In Quadratic polynomial,
We know that,
quadratic polynomial = x² - ( α + β )x + α × β
➝ x² - 4 . x + 1
➝ x² - 4x + 1
Hence, required polynomial will be x² - 4x +1.