Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.-5/6,-2/3
Answers
Answer:
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² –(1/4)x -1 = 0
Multiply by 4 to remove denominator we get
4x² - x -4 = 0
(ii) √2 , 1/3
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² –(√2)x + 1/3 = 0
Multiply by 3 to remove denominator we get
3x² - 3√2 x + 1 = 0
(iii) 0, √5
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² –(0)x + √5 = 0
simplify it we get
x² + √5 = 0
(iv) 1,1
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² –(1)x + 1 = 0
simplify it we get
x² - x + 1 = 0
(v) -1/4 ,1/4
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² –(-1/4)x + 1/4 = 0
multiply by 4 we get
4x² + x + 1 = 0
(vi) 4,1
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² –(4)x + 1 = 0
x^2 –4x + 1 = 0