Question

Find a quadratic polynomial each with the given numbers as the sum of product of its zeros respectively a 2 minus root 3 minus 2 root 3

Answer 1

Step-by-step explanation:

ANSWER

(i) 41, -1

Using the quadratic equation formula,

x2−(Sum  of  root)x+(Product  of  root)=0

Substitute the value in the formula, we get

x2−41x−1=0

4x2−x−4=0

(ii) 2,31

Using the quadratic equation formula,

x2−(Sum  of  root)x+(Product  of  root)=0

Substitute the value in the formula, we get

x2−2x+31=0

Multiply by 3 to remove denominator, 

3x2−32x+1=0

(iii) 0, 5

Using the quadratic equation formula,

x2−(Sum  of  root)x+(Product  of  root)=0

Substitute the value in the formula, we get

x2−0x+5=0

x2+5