Question

find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively (7,-18)

Answer 1

Answer:

${x}^{2} - 7x - 18 = 0$

Step-by-step explanation:

$s = 7 \: \: \: \: \: \: \: p = - 18 \\ \\ equation \: \: \: {x}^{2} - sx + p = 0 \\ \\ {x}^{2} - 7x + ( - 18) = 0 \\ {x}^{2} - 7x - 18 = 0$