find a quadratic polynomial each with the given numbers as the sum and product of its zeros -9/2 and -3/2
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Answered by
2
Hey
Here is your answer,
Sum of zeroes= -9/2
Product of zeroes= -3/2
Quadratic polynomial = x^2 - (Sum of zeroes) x + product of zeroes
=x^2 -(-9/2)x + (-3/2)
= X^2 +9x/2 -3/2
=2x^2 +9 x -3
Hope it helps you!
Here is your answer,
Sum of zeroes= -9/2
Product of zeroes= -3/2
Quadratic polynomial = x^2 - (Sum of zeroes) x + product of zeroes
=x^2 -(-9/2)x + (-3/2)
= X^2 +9x/2 -3/2
=2x^2 +9 x -3
Hope it helps you!
Answered by
0
Heya !!!
Sum of zeroes = -9/2
And,
Product of zeroes = -3/2
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X² - (-9/2)X + ( -3/2)
=> X² + 9X/2 - 3/2
=> 2X² + 9X - 3
★ HOPE IT WILL HELP YOU ★
Sum of zeroes = -9/2
And,
Product of zeroes = -3/2
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X² - (-9/2)X + ( -3/2)
=> X² + 9X/2 - 3/2
=> 2X² + 9X - 3
★ HOPE IT WILL HELP YOU ★
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