Question

find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively:
i)2/3,-4
ii) _1/√2,1/√2
iii) √5,-2
iv) -1/√2,2/3
I want correct answer plz​

Answer 1

$The value of k is -10      </p><p></p><p>Step-by-step explanation:</p><p></p><p>Given : Quadratic polynomial x^2+3x+kx2+3x+k</p><p></p><p>One of the root is 2</p><p></p><p>To find : The value of k</p><p></p><p>Solution :</p><p></p><p>Let the given quadratic polynomial be  f(x)=x^2+3x+kf(x)=x2+3x+k</p><p></p><p>Given one of the zero of the quadratic polynomial is 2.</p><p></p><p>Hence f(2) = 0</p><p></p><p>Put x = 2 in f(x), we get</p><p></p><p>f(2)=2^2+3(2)+kf(2)=22+3(2)+k</p><p></p><p>0=4+6+k0=4+6+k</p><p></p><p>0=10+k0=10+k</p><p></p><p>k=-10k=−10</p><p></p><p>Therefore, The value of k is -10.</p><p></p><p>$

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Answer 2

Answer:

$(55)xy. - 2 {xy >}^{xy < > 3.2 {2. {2 {?}^{2} }^{?} }^{?} ?} { {. = 2222x22222x2x2}^{?} }^{2}$

Step-by-step explanation:

${2125}^{? { {5 {2568}^{?} 33230106232^{?} }^{?} }$