Find a quadratic polynomial each with the given numbers as the sum and
product of its zeroes respectively root3 and -root3
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Answer:
3×2-10x-3
Step-by-step explanation:
Given: Sum of zeroes =α+β=310
Product of zeroes =αβ=−1
Then, the quadratic polynomial =x2−( sum of zeroes )x+ product of zeroes =x2−(310)x+(−1)
=x2−310x−1
=33x2−10x−3
We can consider 3x2−10x−3 as required quadratic polynomial.
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