Question

Find a quadratic polynomial each with the given numbers as the sum And product of its zeroes respectively: (a) −1 6 , 1 6 (b) -5, √5​

Answer 1

Answer:

(i)1/4, -1

Now formula of quadratic equation is

x²-(Sum of root)x + (Product of root) = 0

Plug the value in formula we get

x² –(1/4)x -1  = 0

Multiply by 4 to remove denominator we get

4x²  -  x  -4  = 0

(ii) √2 , 1/3

Now formula of quadratic equation is

x²-(Sum of root)x + (Product of root) = 0

Plug the value in formula we get

x² –(√2)x  + 1/3  = 0

Multiply by 3 to remove denominator we get

3x²  - 3√2 x + 1  = 0

(iii) 0, √5

Now formula of quadratic equation is

x²-(Sum of root)x + (Product of root) = 0

Plug the value in formula we get

x² –(0)x  + √5  = 0

simplify it we get

x²   + √5  = 0

(iv) 1,1  

Now formula of quadratic equation is

x²-(Sum of root)x + (Product of root) = 0

Plug the value in formula we get

x² –(1)x  + 1  = 0

simplify it we get  

x²  -  x + 1  = 0

(v) -1/4 ,1/4

Now formula of quadratic equation is

x²-(Sum of root)x + (Product of root) = 0

Plug the value in formula we get

x² –(-1/4)x  + 1/4  = 0

multiply by 4 we get

4x²   +  x + 1  = 0

Answer 2

Answer:

a)-16,16

Step-by-step explanation:

-16+16 = 16-16 (- , + = -) is formula

=0

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