Question

find a quadratic polynomial each with the numbers as the sum and product of its zeros respectively .. -3 and -2​

Answer 1

Answer:

K [x² + 3x - 2]

Step-by-step explanation:

Sum (α+β) = -3

Product (αβ) = -2

Polynomial = K [x² - (α+β)x + αβ]

K here is a constant

==: K [x² - (-3)x + (-2)]

==: K [x² + 3x - 2]

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