find a quadratic polynomial having the sum and product of zeros are 1/6 and -1/3 respectively
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given that
α+β=1/6
αβ= -1/3
now,
k {x² - (α+β)x + (αβ)}
k{x²-(1/6)x +(-1/3)}
k/6 {6x² - x +(-1)}
so the eq is 6x²-x-1.
i hope this help u
α+β=1/6
αβ= -1/3
now,
k {x² - (α+β)x + (αβ)}
k{x²-(1/6)x +(-1/3)}
k/6 {6x² - x +(-1)}
so the eq is 6x²-x-1.
i hope this help u
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