Find a quadratic polynomial having zero 3 and -4 respectively
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let a and b be the roots of the quadratic equation.
then a=3 and b=-4
equation = x²-(a+b)x + ab
therefore equation is
x²-(3-4)x + 3*-4=0
x²-x-12=0
hope this helps...!
then a=3 and b=-4
equation = x²-(a+b)x + ab
therefore equation is
x²-(3-4)x + 3*-4=0
x²-x-12=0
hope this helps...!
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