Question

find a quadratic polynomial having zeroes -3 and 2​

Answer 1

Hello ....

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=> α + β = -b/a

-3 + 2 = -b/a

-1 / 1 = -(+1) / 1

=> α×β = c /a

-3×2 = c / a

-6 /1 = -6 /1

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we know that quadratic equation is in the form of

$a {x}^{2} + bx + c$

so,

b = 1

C = -6

a = 1

hence , the required number is

$1 {x}^{2} + 1x - 6$

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