find a quadratic polynomial having zeros -4and 3
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Step-by-step explanation:
the answer is as follows
(x+4)(x-3)
=x²+x-12
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Answered by
0
Answer:
x² + x - 12
Step-by-step explanation:
Zeroes are -4 and 3
Quadratic polynomial
=> Sum of zeroes = -4 + 3
= -1
=> Product of zeroes = (-4)(3)
= -12
The quadratic polynomial is of the form,
→ x² - (sum of zeroes)x + (product of zeroes)
→ x² - (-1)x - 12
→ x² + x - 12
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