Math, asked by Ashintahoro, 4 months ago

find a quadratic polynomial having zeros -4and 3​

Answers

Answered by raghavpaltanwale
0

Step-by-step explanation:

the answer is as follows

(x+4)(x-3)

=x²+x-12

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Answered by snehitha2
0

Answer:

x² + x - 12

Step-by-step explanation:

\boxed{Given,}

Zeroes are -4 and 3

\boxed{To \ find,}

Quadratic polynomial

\boxed{Solution,}

=> Sum of zeroes = -4 + 3

                              = -1

=> Product of zeroes = (-4)(3)

                                    = -12

The quadratic polynomial is of the form,

→ x² - (sum of zeroes)x + (product of zeroes)

→ x² - (-1)x - 12

→ x² + x - 12

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