Question

find a quadratic polynomial if the zeroes are 2 and -1/3 respectively​

Answer 1

Answer:

quadratic equation generater formula is,

x^2-(a+b)x+ab. (a=2,b=-1/3)

x^2-(2-1/3)x+2×-1/3

x^2-(2/3)x-2/3

x^2-2/3x-2/3. (ans)

Answer 2

Step-by-step explanation:

x=2               and         x= -1/3

So,

(x-2)=0         and         (x+1/3)=0  are factors of the polynomial

Then,

p(x)=[(x-2)(x+1/3)]k

    =[x²-2x+x/3-2/3]k

    =[x²-5x/3 -2/3]k

    =3x²-5x-2                       [where k=3]