Find a quadratic polynomial if the zeroes of it are 2and -1/3 respectively
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(x-2)(x+1/3) =(x2-5/3x-2/3) is the quardratic polynomial
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given zeros= 2, -1/3
then,
a general quadratic polynomial with roots a and b is
x^2-(α+β)x+αβ
here,
a=α, β=-1/3
by substituting values of α and β, we have,
x^2 -(α+β)x +αβ
x^2 -(2 - 1/3)x + (2)(-1/3)
x^2 - 5/3x -2/3
or
3x^2 -5x -2.
hope it helps.
then,
a general quadratic polynomial with roots a and b is
x^2-(α+β)x+αβ
here,
a=α, β=-1/3
by substituting values of α and β, we have,
x^2 -(α+β)x +αβ
x^2 -(2 - 1/3)x + (2)(-1/3)
x^2 - 5/3x -2/3
or
3x^2 -5x -2.
hope it helps.
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