Math, asked by sa0598797, 1 month ago

find a quadratic polynomial in 'y' ​

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Answers

Answered by NITESH761
1

Answer:

x²-5/3x-2=0

Step-by-step explanation:

\Large\underline\mathsf{Given:-}

  • Sum of zeros= 5/3
  • product of zeros= -2

\Large\underline\mathsf{To\:Find:-}

Quadratic polynomial

\Large\underline\mathsf{Solution:-}

Sum of zeros = -b/a

product of zeros = c/a

ax²+bx+c=0

we are given two equation and 3 variable So it is impossible to solve

So, we have to assume 1 variable, because there are infinite number of quadratic equations that we can form

let's assume a=1

sum of zeros= -b

product of zeros=c

put the values

ax²+bx+c=0

x²+(-5/3)x+(-2)=0

x²-5/3x-2=0

Your equation is :-

 {x}^{2}  -  \frac{5}{3} x - 2 = 0

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