find a quadratic polynomial in 'y'
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Answer:
x²-5/3x-2=0
Step-by-step explanation:
- Sum of zeros= 5/3
- product of zeros= -2
Quadratic polynomial
Sum of zeros = -b/a
product of zeros = c/a
ax²+bx+c=0
we are given two equation and 3 variable So it is impossible to solve
So, we have to assume 1 variable, because there are infinite number of quadratic equations that we can form
let's assume a=1
sum of zeros= -b
product of zeros=c
put the values
ax²+bx+c=0
x²+(-5/3)x+(-2)=0
x²-5/3x-2=0
Your equation is :-
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