Find a quadratic polynomial of sum of whose zeros are 2 and product is minus 8 hence find the zeros of the polynomial
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The zeroes are 4 and -2
P(x)=x^2-2x-8
P(x)=x^2-2x-8
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Answer:
p(x) =Axis square minus sum of zero X + product
x2-2x+(-8)
x2-2x-8
x2(-4x-2x)-8
x(x-4)+2(x-4)
(x-4)(x+2)
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