find a quadratic polynomial one of whose zeros is (3+√2) and the sum of its zeroes is 6.
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Let @ and ß be the zeros of the polynomial
Given that,
One of the zero is 3+√2
i.e.,@=3+√2
and the sum of zeros is 6
i.e.@+ß=6.............[1]
Substituting the value of @ in [1],
→(3+√2)+ß=6
→ß=6-(3+√2)
→ẞ=3-√2
Here,(@,ß)=(3+√2,3-√2)
Now,
Product of zeros:
@ß
=(3+√2)(3-√2)
=3²-√2²
=9-4
=5
★Required Polynomial:
x²-(Sum of zeros)x+Product of zeros
=x²-6x+5
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