Question

Find a quadratic polynomial p(x) with -81 and 3 as product and one of the zeroes respectively.​

Answer 1

Answer:

Step-by-step explanation:

Let a and b ne two zeroes of p(x)

So, a×b = Product of zeroes

Let a be 3 be the first zero of p(x)

Therefore,

3×b= -81

b = -27

So, Sum of zeroes = a+b

= 3+(-27)

= -24

Required polynomial:

x^2 - Sx +P

= x^2 + 24 - 81

HOPE THIS HELPS YOU!!!