Question

find a quadratic polynomial p(y) whose sum and product of zeros are 3 and -1/3 respectively

Answer 1

alpha + bita =3

alpha*bita=-1/3.

x2 -(alpha + bita)x+alpha*bita
x2-3x -1/3
3x2-9x -1/3 =0
3x2-9x-1=0

Answer 2

Hi,

Here is your answer

Sol :
α, β are zeros of the quadratic polynomial then sum and product of whose zeroes are 3 and -1/3 respectively.
∴ α + β = 3 αβ = -1/3
α, β are zeros of the quadratic polynomial then the equation is x2 -(α + β)x + αβ = 0
x2 -( 3 ) x + ( -1/3 ) = 0

(It's X square where I wrote x2 for convenience)

hoping it helps

:D