Question

find a quadratic polynomial sum and product of zeroes are -3 and 2 respectively.​

Answer 1

Answer:

$9</p><p></p><p>3x2+ax−2=0</p><p></p><p>Since, one root is 1, then x=1</p><p></p><p>⇒  3(1)2+a(1)−2=0</p><p></p><p>⇒  3+a−2=0</p><p></p><p>⇒  a+1=0</p><p></p><p>⇒  a=−1</p><p></p><p>⇒  Now, it is given that ax2+6ax−b=0 has equal roots.</p><p></p><p>∴  b2−4ac=0</p><p></p><p>⇒  (6a)2−4(a)(−b)=0</p><p></p><p>⇒  36a2+4ab=0</p><p></p><p>⇒  36(−1)2+4(−1)b=0                 [ Substituting a=−1 ]</p><p></p><p>⇒  36−4b=0</p><p></p><p>⇒  4b=36</p><p></p><p>∴  b=9</p><p></p><p>$

hopefully it will help u