Question

Find a quadratic polynomial, sum of whose zeores is 8 and product is 12.
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Answer 1

Answer:

x^2 - 8x + 12

Step-by-step explanation:

The general form of polynomial = k(x^2 - (alpha + beta)x + alpha x beta)

Given :

alpha + beta = 8 and alpha x beta = 12

=> 1(x^2 - 8x + 12)

=> x^2 - 8x + 12 (We can ignore k as it is constant)

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Answer 2

Hi

Always remember this formula whenever u go for such questions next time -

FORMULA FOR FRAMING A QUADRATIC POLYNOMIAL WHEN THE SUM AND PRODUCT OF ZEROES ARE GIVEN

k{x²-(Sum of zeroes)x+(Product of zeroes)}

Where k is a constant

Here, sum of zeroes=8

Product of zeroes=12

Thus, the required quadratic polynomial

=k{x²-(Sum of zeroes)x+(Product of zeroes)}

=k{x²-8x+12}

=x²-8x+12, where k=1

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