Math, asked by pintupanchalpanchal1, 10 months ago

find a quadratic polynomial,the sum and product of whoes zeros are the following numbers 1.
 - 3 < 2

Answers

Answered by zahaansajid
4

The given conditions if the zeroes are α and β is,

α+β = -3

αβ = 2

If α and β are the zeroes,

then the quadratic equation will be

(x-α)(x-β) = x² - x(α+β) + αβ

Hence the quadratic equation here would be

x² - x(-3) + (2) = x² +3x +2

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Answered by Anonymous
9

\huge\frak{\underbrace{\overbrace{\red{Your\:Answer}}}}

sum of 2+√3 and 2-√3 is

2 +  \sqrt{3}  + 2 -  \sqrt{3}  \\  = 4

and product of 2+√3 and2-√3

(2 +  \sqrt{3} )(2 -  \sqrt{3} ) \\ 2(2 -  \sqrt{3} ) +  \sqrt{3} (2 -  \sqrt{3} ) \\ 4 - 2 \sqrt{3}  + 2 \sqrt{3}  -  \sqrt{9}  \\ 4 - 3 \\ 1

\bold{hope\:it\:helps\:}

\huge\frak{\underline{\underline{\red{Thanks:)}}}}

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