Math, asked by AA69, 1 year ago

Find a quadratic polynomial , the sum and product of whoes zeroes are -3 and 5 respectively .

plz help me !!!


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rakeshmohata: 64x² - 1 = 0
rakeshmohata: (8x)² - (1)² = 0
rakeshmohata: (8x - 1)(8x +1) = 0
rakeshmohata: so either x = 1/8 or.. x =-1/8
rakeshmohata: since the real root is positive... so x = 1/8
rakeshmohata: and hence © is the answer
nandutry: hii

Answers

Answered by Anonymous
3
x {}^{2} + 3x + 5
if u like please make me BRAINLIEST
x2 - (sum of zeroes)x + product of zeroes
now put the value of sum of zeroes and product of zeroes

Anonymous: ok bye
Anonymous: Hyderabad
Answered by rakeshmohata
5
Hope u like my process
=====================
Let one of the root be a

So, the other root be b

According to the problem
---------------------------------------
 =  > a + b =  - 3.......(1) \\  \\  =  > ab = 5 \\  \\
Now.,
=-=-=-
For a quadratic equation,

x² - (sum of the zeroes)x +(product of zeroes) =0

So,

=> x² - (a+b) + ab =0

or, x² - (-3)x +5 =0

or, x² + 3x + 5 = 0___(answer)

__________________________
Hope this is ur required answer

Proud to help you

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