Question

Find a quadratic polynomial, the sum and product of whose zeroes are √2and 1/3 respectively.​

Answer 1

Answer:

X^2 - root2x + 1/3

Srry for it being unclear but i cnt seem to write it properly

Step-by-step explanation:

Answer 2

$\huge \fcolorbox{red}{pink}{Solution :)}$

Given ,

Sum of roots = √2

Product of roots = 1/3

We know that ,

$\large \mathtt{\fbox{ {(x)}^{2} - (sum \: of \: roots)x + (product \: of \: roots) }}$

Substitute the known values , we get

(x)² - √2x + 1/3

Hence , the quadratic equation is (x)² - √2x + 1/3 = 0

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