Question

Find a quadratic polynomial, the sum and product of whose zeroes are

−1/12 and 1/3, respectively​

Answer 1

Answer:

$k ({x}^{2} - ( - \frac{1}{12x} ) + \frac{1}{3}) \\ k( \frac{12 {x}^{2} + 1x + 4 }{12} ) \\ \\ here \: the \: value \: of \: k \: is \: 12 \\ 12 {x}^{2} + 1x + 4$