Question

Find a quadratic polynomial the sum and product of whose zeros are 2 and -3/2 respectively. also find zeroes

Answer 1

Hi Mate !!

Here's ur ans :-

Sum of the Zeros = 2
Product of the Zeros = ( - 3 /2 )

• To form the quadratic equations we have formula as :-

x² - ( Sum of Zeros )x +(Product of Zeros )

Putting values in it ¡¡


${x}^{2} - 2x + ( \frac{ - 3}{2} ) = 0$

$\frac{2 {x}^{2} - 4x - 3 }{2} = 0$


2x² - 4x - 3 = 0 is the required quadratic equation.

• To Factorising use Shree Dhracharya method!!

D = b² - 4ac

= ( - 4 )² - 4 × 2 × ( - 3 )

= 16 + 24

= 40

° x = ( - b ± √ D ) / 2a

x = ( 4 ± √ 40 ) / 2a

x = ( 4 ± 2√10 ) / 2 × 2

x = 2 ( 2 ± √10 )/4

x = ( 2 ± √10 ) / 2

So, the Zeros of the polynomial is :-

$\frac{2 + \sqrt{10} }{2} \: \: and \: \: \frac{2 - \sqrt{10} }{2}$