Question

Find a quadratic polynomial, the sum and product of whose zeroes are -8 and 12
respectively. Hence find the zeroes.

Answer 1

Answer:

${x }^{2} + 8x + 12$

Step-by-step explanation:

$\alpha + \beta = - 8 \\ \alpha \beta = 12 \\ k(x {}^{2} - ( \alpha + \beta )x + \alpha \beta ) \\ k(x {}^{2} - ( - 8)x + 12 \\ k(x {}^{2} + 8x + 12) \\ let \: k = 1 \\ therefore \: \: \: \: \: \: \: \: x {}^{2} + 8x + 12$